How to calculate the charging terminal power of electric vehicle charging pile？

• Power Unit (charging cabinet): One cabinet integrates 36 × 30 kW = 1080 kW of DC capacity.

• Dispenser: A pedestal that hosts one or two DC connectors (“guns”).

• Cable current rating: Typically 200 A; liquid-cooled “ultrafast” options up to 600 A (spec-dependent).

• DC voltage window:150–1000 V; the actual operating voltage follows the vehicle pack/BMS.

• 00 V × 200 A = 80 kW

• 800 V × 200 A = 160 kW

• 1000 V × 200 A = 200 kW

• 857 V × 200 A ≈ 171 kW

  With liquid-cooled 600A current (spec-dependent)

• 1000 V × 600 A = 600 kW（theoretical; thermal/nameplate may limit)

• 685 V × 350 A ≈ 240 kW（correction to common 140 kW typo) 

Scenario A: 6 EVs @ 800 V × 200 A≈ 160 kW each; total ≈ 960 kW< 1080 kW → all satisfied.

Scenario B: 6 EVs @ 1000 V × 200 A, 200 kW nameplate

Requested = 1200 kW> 1080 kW; equal sharing ⇒ ≈180 kW/EV (or use priority logic).

Q1：Why does power on the same connector fluctuate?
A：The vehicle BMS dynamically adjusts current with SOC, temperature, and cell health. Ambient temperature also affects the cable’s continuous current capability and thermal limits.

Q2：On an “800 V platform,” is power always 200 A × 800 V = 160 kW?
A：Not necessarily. Actual voltage varies with SOC, the BMS may limit current, and you’re still bounded by the dispenser nameplate and Power Unit allocation.

Q3：If a dispenser is rated “200 kW,” can a 400 V passenger car always charge at 200 kW?
A：With a 200 A cable and ~400 V battery, power is about 80 kW. Reaching 200 kW requires higher voltage or higher current (e.g., 600 A liquid-cooled), and the dispenser must allow it.